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V(L)
V = 150 /1000 = 0.150 L
Mm KClO3 = 122.5 g/mol
mol = masa/Mm
mol = 2 g / 122.5 g/mol
mol = 0.0163 de KClO3
M = 0.0163 mol
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0.150 L
M = 0.108 mol/L