La fórmula empírica del compuesto es CH. Si la masa molar de este compuesto es aproximadamente 78 g, ¿cuál sería su fórmula molecular?
1. FE: CH
2. calcular Mm FE
C: 1 x 12 = 12 g/mol
H: 1 x 1 = 1 g/mol
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Mm = 13 g/mol
2. calcular n
n = Mm compuesto / Mm FE
n = 78 g/mol ÷ 13 g/mol
n = 6
3. FM: (CH)6 = C6H6
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La fórmula empírica del compuesto es CH. Si la masa molar de este compuesto es aproximadamente 78 g, ¿cuál sería su fórmula molecular?
1. FE: CH
2. calcular Mm FE
C: 1 x 12 = 12 g/mol
H: 1 x 1 = 1 g/mol
````````````````````````````````````````````
Mm = 13 g/mol
2. calcular n
n = Mm compuesto / Mm FE
n = 78 g/mol ÷ 13 g/mol
n = 6
3. FM: (CH)6 = C6H6