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ⁿ⊿ ª₁
ª₂
Donde:
n = Hipotenusa = Diagonal = D = 6.8 cm
a₁ = Cateto Opuesto (CO) = altura = h
a₂ = Cateto Adyacente (CA) = base = b = 6 cm
Resolvemos
h = √[D² - b²]
h = √[6.8² - 6²]
h = √[10.24]
h = 3.2 cm
La altura mide 3.2 cm