Respuesta:
Explicación paso a paso:
Let y = log cosex^2x/2
=> dy/dx = 1/cosec^2x/2 . 2 cosecx/2 . (-cotx/2cosecx/2) .1/2
=> dy/dx = -sin^2x/2.cotx/2cosec^2x/2 = -cotx/2 × 1
=> dy/dx = -cotx/2
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Respuesta:
Explicación paso a paso:
Let y = log cosex^2x/2
=> dy/dx = 1/cosec^2x/2 . 2 cosecx/2 . (-cotx/2cosecx/2) .1/2
=> dy/dx = -sin^2x/2.cotx/2cosec^2x/2 = -cotx/2 × 1
=> dy/dx = -cotx/2