sen(2x+10°)=cos(x+20°) Entonces quiere decir que 2x + 10 + x + 20 = 90
3x = 60 -----> x = 20
Sen 3x = sen 60
Cos 6 x = cos 120
√3 / - 0,5 Rpta = -2√3
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sen(2x+10°)=cos(x+20°) Entonces quiere decir que 2x + 10 + x + 20 = 90
3x = 60 -----> x = 20
Sen 3x = sen 60
Cos 6 x = cos 120
√3 / - 0,5 Rpta = -2√3