Question

Nilai dari sin310° - sin190° /cos310° + cos190°

Answer 1

Verified answer

= sin 310 - sin 190÷ cos 310 + cos 190
=  2cos(250)sin(60) ÷ 2cos(250)cos(60)
= sin60 ÷ cos 60
= 1/2√3 ÷ 1/2
= √3

Answer 2

Jawab

sin A - sin B =  2  cos 1/2 (A+B) sin 1/2 (A - B)
cos A + cos B = 2 cos 1/2(A+B) cos 1/2(A - B)

maka (sin A - sin B)/ (cos A + cos B) =  tan 1/2 (A - B)

(sin 310 - sin 190) / (cos 310 + cos 190) = tan 1/2 (310 - 190)
= tan 1/2 (120)
= tan 60
= √3