Odpowiedź:
= [tex]\frac{tg(90^o + 60^o) + cos ( 90^o + 30^o)}{cos( 90^o + 45^o) + sin 90^o}[/tex] [tex]= \frac{- ctg 60^o - sin 30^o}{- sin 45^o + sin 90^o} =[/tex]
[tex]= \frac{- \frac{\sqrt{3} }{3} - \frac{1}{2} }{- \frac{\sqrt{2} }{2} + 1} =[/tex][tex]\frac{- 2\sqrt{3}- 3 }{6 - 3\sqrt{2} } *\frac{6 + 3\sqrt{2} }{6 + 3\sqrt{2} } =[/tex] [tex]\frac{- 12\sqrt{3} - 6\sqrt{6} - 18 - 9\sqrt{2} }{36 - 9*2} = - \frac{2}{3} \sqrt{3} - \frac{1}{3} \sqrt{6} - 1 - \frac{1}{2} \sqrt{2}[/tex]
Szczegółowe wyjaśnienie:
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Odpowiedź:
= [tex]\frac{tg(90^o + 60^o) + cos ( 90^o + 30^o)}{cos( 90^o + 45^o) + sin 90^o}[/tex] [tex]= \frac{- ctg 60^o - sin 30^o}{- sin 45^o + sin 90^o} =[/tex]
[tex]= \frac{- \frac{\sqrt{3} }{3} - \frac{1}{2} }{- \frac{\sqrt{2} }{2} + 1} =[/tex][tex]\frac{- 2\sqrt{3}- 3 }{6 - 3\sqrt{2} } *\frac{6 + 3\sqrt{2} }{6 + 3\sqrt{2} } =[/tex] [tex]\frac{- 12\sqrt{3} - 6\sqrt{6} - 18 - 9\sqrt{2} }{36 - 9*2} = - \frac{2}{3} \sqrt{3} - \frac{1}{3} \sqrt{6} - 1 - \frac{1}{2} \sqrt{2}[/tex]
Szczegółowe wyjaśnienie: