Question

Sin 2B - sin 4B + sin 6B / cos 2B - cos 4B + cos 6B = tan 4B

Answer 1

Verified answer

Jawab

(sin 2B  - sin 4B + sin 6B)/(cos 2B - cos 4B + cos 6B) =
= (sin 6B + sin 2B) - sin 4B  / (cos 6B +cos 2B) - cos 4B
= {(2 sin 4B cos 2B) - sin 4B)  / {(2 cos 4B cos 2B) - cos 4B}
=  sin 4B ( 2 cos B - 1)  / cos 4B ( 2 cos 2B -1)
= sin 4B/ cos 4B
= tan 4B