Question

Sin 150 derajat + sin 120 derajat / cos 210 derajat - cos 300 derajat =

Answer 1

Sin 150 = sin(180-30)= sin 30 = 1/2
sin 120 = sin(180-60)= sin 60 = 1/2 √3

cos 210 = cos (180+30) = - cos 30 = -1/2 √3
cos 300 = cos (360 -60) = cos 60 = 1/2

p = sin150 + sin 120 = 1/2 + 1/2 √3
q = cos 210 - cos 300 = -1/2√3 - 1/2  = - (1/2 + 1/2 √3)

p/q = (1/2 + 1/2√3)  /  -(1/2 + 1/2√3) 
p/q = -1