Explicación paso a paso:
[tex]5 < 2x + 7 \leqslant 15 \\ 5 - 7 < 2x + 7 - 7 \leqslant 15 - 7 \\ - 2 < 2x + 0 \leqslant 8 \\ - 2 < 2x \leqslant 8 \\ \frac{ - 2}{2} < \frac{2x}{2} \leqslant \frac{8}{2 } \\ - 1 < x \leqslant 4[/tex]
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Verified answer
Explicación paso a paso:
[tex]5 < 2x + 7 \leqslant 15 \\ 5 - 7 < 2x + 7 - 7 \leqslant 15 - 7 \\ - 2 < 2x + 0 \leqslant 8 \\ - 2 < 2x \leqslant 8 \\ \frac{ - 2}{2} < \frac{2x}{2} \leqslant \frac{8}{2 } \\ - 1 < x \leqslant 4[/tex]