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x = 20 : 5 ≤ 4
y = 20 : 4 ≤5
2. 6x+y≤12
x = 12 : 6 ≤ 2
y = 12 :1 ≤ 12
3. x ≥ 0
4 y ≥ 0
6x + y ≤ 12
x ≥ 0
y ≥ 0
dari persamaan diperoleh
5x + 4y ≤ 20
titik potong: (0,5) dan (4,0)
6x + y ≤ 12
titik potong: (0,12) dan (2,0)