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b) (2x2 – 3x + 2) + (4x2 – 5x + 1)
c) (3a2 + 5) – (4a2 – 3a + 2)
Penyelesaian:
a) –4ax + 7ax
= (–4 + 7)ax
= 3ax
b) (2x2 – 3x + 2) + (4x2 – 5x + 1)
= 2x2 – 3x + 2 + 4x2 – 5x + 1
= 2x2 + 4x2 – 3x – 5x + 2 + 1
= (2 + 4)x2 + (–3 – 5)x + (2 + 1
)= 6x2 – 8x + 3
c) (3a2 + 5) – (4a2 – 3a + 2
)= 3a2 + 5 – 4a2 + 3a – 2
= 3a2 – 4a2 + 3a + 5 – 2
= (3 – 4)a2 + 3a + (5 – 2
)= –a2 + 3a + 3
4A+7B+9
3X+4B+5
10A+8Y+7
6A+4B+11