A I.P B
[tex]6 \times (a + 1) = (a - 1) \times 8 = {k}^{2} \times 12 \\ [/tex]
[tex]6 \times (a + 1) = (a - 1) \times 8 \\ 6a + 6 = 8a - 8 \\ 6 + 8 = 8a - 6a \\ 14 = 2a \\ \frac{14}{2} = a \\ \boxed{7 = a}[/tex]
[tex]6 \times (a + 1) = {k}^{2} \times 12 \\ 6 \times (7 + 1) = {k}^{2} \times 12 \\ 6 \times 8 = {k}^{2} \times 12 \\ 48 = {k}^{2} \times 12 \\ \frac{48}{12} = {k}^{2} \\ 4 = {k}^{2} \\ \sqrt{4} = k \\ \boxed{2 = k}[/tex]
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☆ RESOLUCIÓN:
A I.P B
[tex]6 \times (a + 1) = (a - 1) \times 8 = {k}^{2} \times 12 \\ [/tex]
[tex]6 \times (a + 1) = (a - 1) \times 8 \\ 6a + 6 = 8a - 8 \\ 6 + 8 = 8a - 6a \\ 14 = 2a \\ \frac{14}{2} = a \\ \boxed{7 = a}[/tex]
[tex]6 \times (a + 1) = {k}^{2} \times 12 \\ 6 \times (7 + 1) = {k}^{2} \times 12 \\ 6 \times 8 = {k}^{2} \times 12 \\ 48 = {k}^{2} \times 12 \\ \frac{48}{12} = {k}^{2} \\ 4 = {k}^{2} \\ \sqrt{4} = k \\ \boxed{2 = k}[/tex]
☆ RESPUESTA:
[tex] \boxed{k = 2}[/tex]