Respuesta:
2
Explicación paso a paso:
BC=12(a) AB = 5(b) AC =x(c)
TEOREMA DE PITAGORAS:
[tex]a^{2}+b^{2}=c^{2}[/tex]
[tex]5^{2}+13^{2} =x^{2} \\25 + 144 = x^{2}\\169= x^{2} \\13 = x[/tex]
TEOREMA DE PONCELET:
a+b=c+2r
12 + 5= 13 + 2r
17 = 13 +2r
4 = 2r
2 = r
Espero te sirva :)
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Verified answer
Respuesta:
2
Explicación paso a paso:
BC=12(a) AB = 5(b) AC =x(c)
TEOREMA DE PITAGORAS:
[tex]a^{2}+b^{2}=c^{2}[/tex]
[tex]5^{2}+13^{2} =x^{2} \\25 + 144 = x^{2}\\169= x^{2} \\13 = x[/tex]
TEOREMA DE PONCELET:
a+b=c+2r
12 + 5= 13 + 2r
17 = 13 +2r
4 = 2r
2 = r
Espero te sirva :)