[tex]A = cos53º \times sec53º+sen37º \times sec53 \\ A = \frac{3}{5} \times \frac{5}{3} + \frac{3}{5} \times \frac{5}{3} \\ A = 1 + 1 \\ A = 2[/tex]
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RESOLUCIÓN:
[tex]A = cos53º \times sec53º+sen37º \times sec53 \\ A = \frac{3}{5} \times \frac{5}{3} + \frac{3}{5} \times \frac{5}{3} \\ A = 1 + 1 \\ A = 2[/tex]
RESPUESTA:
[tex]b) \: 2[/tex]