Question

Composición porcentual Cu(No3)2

Answer 1

Cu= 1 x 63.54 = 63,54 g/mol

N =  2 x 14 = 28 g/mol

O = 6 x 16 = g/mol = 96 g/mol

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Mm  Cu(NO3)2 =  187,54 g/mol

Cobre:

187,54 g  ----- 100 %

 63,54 g  -----     x

X = 33.88 % de Cu

Nitrógeno:

 

187,54 g  ----- 100 %

        28 g  -----     x

X = 14.93  % de N

 

Oxigeno:

 

187,54 g  ----- 100 %

        96 g  -----     x

X = 51.18  % de O