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3(x*y) = 3xy
y tenemos un cuadrado de de:
(x-y)(x-y) = (x-y)²
(x-y)² = x²-2xy+y²
Sumando los 2 queda
(x²-2xy+y²) + (3xy)
x²-2xy+y² + 3xy
x²+xy+y²
Resultado
x² +y² +xy
Saludos!!!