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(√5 + √3)² = √5² + 2 √5 √3 + √3²
= 5 + 2√15 + 3
= 8 + 2√15 , no se puede más
suerte
(√5 + √3)² Aplicamos productos notables (a + b)² = a² + 2ab +b²
(√5 + √3)² = (√5)² +2√5√3 +(√3)² =
5 + 2√5*3 + 3 =
8 + 2 √15 = Saco factor comun 2
2(4 +√15)
Solucion:
2( 4 + √15)