Respuesta:
Es la c
Explicación paso a paso:
Dados los conjuntos:
A = {x ∈ N/x es un numero impar x < 14}
B = {x/x ∈ N, 5 < x ≤ 20}
Determina A∩B
Hallamos A:
A = {1,3,5,7,9,11,13}
Hallamos B:
B = {6,7,8,9,10,11,12,13,14,15,16,17,18,19,20}
Calculamos A∩B:
A∩B = {7, 9, 11, 13}
Por lo tanto, el valor de A∩B es {7, 9, 11, 13}
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Verified answer
Respuesta:
Es la c
Explicación paso a paso:
Dados los conjuntos:
A = {x ∈ N/x es un numero impar x < 14}
B = {x/x ∈ N, 5 < x ≤ 20}
Determina A∩B
Hallamos A:
A = {x ∈ N/x es un numero impar x < 14}
A = {1,3,5,7,9,11,13}
Hallamos B:
B = {x/x ∈ N, 5 < x ≤ 20}
B = {6,7,8,9,10,11,12,13,14,15,16,17,18,19,20}
Calculamos A∩B:
A = {1,3,5,7,9,11,13}
B = {6,7,8,9,10,11,12,13,14,15,16,17,18,19,20}
A∩B = {7, 9, 11, 13}
Por lo tanto, el valor de A∩B es {7, 9, 11, 13}