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sen (60+45)
SEN(A+B)=senAcosB+CosASenB
entonces
sen (60+45)=sen60cos45+cos60sen45
(√3/2/)(√2/2)+(1/2)(√2/2)
√6/4+√2/4=(√6+√2)/4=(2.45+1.41)/4
3.86/4=0.965