¿como saco el mol de muestra de 6.0 g de Ag.... Question from @gordillcarpio22

September 2018 2 12 Report

¿como saco el mol de muestra de 6.0 g de Ag

jmax15 1
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6.0 g de Ag x 107,87 g/mol

0 votes Thanks 1

snorye M = 6.0 g
Mm Ag = 107.8 g/mol

n = masa / Mm
n(moles= 6 g / 107.8 g/mol

n = 0.0556 mol de Ag

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