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x(x + 3) = - 9
x² + 3x = - 9
x² + 3x + 9 = 0
Utilizas la formula
a = 1
b = 3
c = 9
x = [- b +/-√(b² - 4ac)]/2a
x = [- 3 +/- √(3² - 4(1)(9)]2*1
x = [ - 3 +/ - √(9 - 36)]/2
x = [ - 3 +/ - √-27]/2 Tiene como solución 2 raices imaginarias
x₁ = [- 3 + √- 27)/2 Pero √- 27 = √(27 * 1 -) = √27 * √- 1 = √27i
x₁ = (- 3 + √27i)/2
o
x² = (- 3 - √27i)/2
Solución.
{(- 3 + √27i)/2 , (- 3 - √27i)/2)