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Sea ax²+bx+c=0:
x = ( -b ± √(b²-4ac) )/(2a)
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Solución:
2x² + 3x = 2
2x² + 3x - 2 = 0
x= ( -3 ± √ (3²-4*2*(-2)) )/(2*2)
x = ( -3 ± 5 )/4
x1= (-3-5)/4 = -2
x2= (-3+5)/4 = 1/2
Solución: x = {-2,1/2}
Saludos!!