Como resuelvo esta ecuación exponencial:
3^2x - 4 [ 3^(x+1) ] = - 27
Porfavor :3
3^2x - 4 [ 3^(x+1) ] = - 27
Porfavor :3
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(3^x)² - 12(3^x) + 27 = 0
Resuelves la ecuación y queda:
x = 1 ó x = 2