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x^4-2x^2+1=0 ⇔ z^2-2z+1=0
z = [ -b ± √(b² -4ac)] / 2a
z = [ 2 ± √((-2)² -4(1)(1))] / 2 = 1 Raíz doble
Se deshace el cambio de variable
Si z =1
x^2=1 ⇒ x = ±√1 ⇔ x = ±1
Las raíces de x^4-2x^2+1 Son 1, 1 , -1 y -1
Solución: x^4-2x^2+1 = 1(x-1)(x-1)(x+1)(x+1)
Verificación:
(x-1)(x-1)(x+1)(x+1) = (x-1)(x+1)(x-1)(x+1) = (x^2-1)(x^2-1) = (x^2-1)^2 = x^4-2x^2+1