Como resolver las siguientes operaciones paso a paso de quimica: - 10 gr de soluto en 200gr de solvente - 275 ml de soluto en 1 L de solvente -37 kg de soluto en 333 kg de solvente -500 gr de soluto en 600 gr de solvente -70 L de soluto en 130 L de solvente
solución: soluto + solvente
solc. = 10 g + 200 g = 210 g
%m/m= masa soluto x 100
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masa solc.
%m/m = 10 g x 100
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200 g
.% m/m = 5 % g/g
2. converti mL a L = 275 / 1000 = 0.275 L
solc = 0.275 L + 1 L =1.275 L
% v/v = v soluto x 100
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v solc.
% v/v = 0.75 L X 100
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1.275 L
% v/v = 21.56 % mL/mL
3. %m/m= masa soluto x 100
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masa solc.
SOLC. = 37 Kg + 333 Kg = 370 Kg
% g/g = 37 Kg x 100
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370 Kg
%g/g = 10 %
4. %m/m= masa soluto x 100
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masa solc.
solc. = 500 g + 600 g = 1100 g
% g/g = 500 g x 100
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1100 g
%g/g = 45.45 % g/g
5. %v/v= v soluto x 100
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v solc.
solc. =70 L + 130 L = 200 L
% v/v = 70 L x 100
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200 L
% v/v = 35 % L/L