Question

como hago
Separar en términos y resolver:
a) (-8) .3:(-6) -15: (-3). (-2)+18: (-1-2)=

Answer 1

Verified answer

Respuesta:

[tex]\left(-8\right)\:\cdot 3:\left(-6\right)\:-15:\:\left(-3\right)\cdot \:\left(-2\right)+18:\:\left(-1-2\right)=\\\\\\=\left(-8\right)\cdot \:3\div \left(-6\right)-15\div \left(-3\right)\left(-2\right)+18\div \left(-3\right)\\\\=4-15\div \left(-3\right)\left(-2\right)+18\div \left(-3\right)\\\\=4-10+18\div \left(-3\right)\\\\=4-10-6\\\\=-12[/tex]

Answer 2

Respuesta:

-12

Explicación paso a paso:

(-8) 3÷(-6) -15÷(-3)(-2)+18÷(-1-2)

1. −8×3÷−6−15÷−3×−2+18÷−3

2. −24÷−6−15÷−3×−2+18÷−3

3. 4−15÷−3×−2+18÷−3

4. 4−(−5×−2)+18÷−3

5. 4−10+18÷−3

6. 4−10−6

7. −6−6

8. −12

Espero que te sirva :)