Como hago la ecuación 2(3x+3)-4(5x-3)=x(x-3)-x(x+5).... Question from @dannyhnao

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August 2018 2 14 Report

Como hago la ecuación 2(3x+3)-4(5x-3)=x(x-3)-x(x+5)

Piscis04 $2(3x+3)-4(5x-3)=x(x-3)-x(x+5) \\ \\ 6x+6-20x+12=x^2-3x-x^2-5x \\ \\ 6+12= -3x-5x-6x+20x \\ \\ 18= 6x \\ \\ \frac{18}{6}=x \to \boxed{x= 3}$

Espero que te sirva, salu2!!!!

2 votes Thanks 2

angiemontenegr Resolver.
2 ( 3x + 3) - 4(5x - 3) = x( x - 3) - x(x + 5) =
6x + 6 - 20x + 12 = x² - 3x -x² - 5x
18 - 14x = - 8x
18 = -8x + 14x
18 = 6x
18/6 = x
3 = x

Respuesta.
x = 3

1 votes Thanks 1