Materi : Bentuk Akar dan Pangkat
A. 3√2 + 5√2 = ( 3 + 5 )√2 = (8)√2 = 8√2
B. 12√3 - 8√3 = ( 12 - 8 )√3 = (4)√3 = 4√3
C. 9√20 - 8√5
= 9√(4.5) - 8√5
= 18√5 - 8√5 = ( 18 - 8 )√5 = (10)√5 = 10√5
D. 3√5 . 8√10
= (3.8)√(5.10)
= 24√(25.2) = (24.5)√2 = 120√2
E. 12√108 ÷ 4√3 = (12/4)√(108/3) = 3√36 = 18
F. √72/(3√2) = ⅓ . √(72/2) = ⅓√36 = 2
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
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Materi : Bentuk Akar dan Pangkat
A. 3√2 + 5√2 = ( 3 + 5 )√2 = (8)√2 = 8√2
B. 12√3 - 8√3 = ( 12 - 8 )√3 = (4)√3 = 4√3
C. 9√20 - 8√5
= 9√(4.5) - 8√5
= 18√5 - 8√5 = ( 18 - 8 )√5 = (10)√5 = 10√5
D. 3√5 . 8√10
= (3.8)√(5.10)
= 24√(25.2) = (24.5)√2 = 120√2
E. 12√108 ÷ 4√3 = (12/4)√(108/3) = 3√36 = 18
F. √72/(3√2) = ⅓ . √(72/2) = ⅓√36 = 2
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]