Ile wynosi stężenie molowe 20%r-ru NaCl o gęstości 1,22g/cm
Cm = 20% *1220g/dm3 / 58,5 * 100 = 4,17mol/dm3
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Cm = 20% *1220g/dm3 / 58,5 * 100 = 4,17mol/dm3