Oblicz stężenie molowe roztworu koh o stężeniu 28% i gęstości d = 1,239 g/cm³.
Cp=28%
d=1,239g/cm3=1239g/dm3
M KOH=56g/mol
Cm=?
Cm=Cp*d/100%*M
Cm=28*1239/100*56
Cm = 6,2mol/dm3
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Cp=28%
d=1,239g/cm3=1239g/dm3
M KOH=56g/mol
Cm=?
Cm=Cp*d/100%*M
Cm=28*1239/100*56
Cm = 6,2mol/dm3