Ile gramów siarczku sodu znajduje sie w 0,5 dm3 roztworu 8% o gestosci 1,1 g/cm3 ??
v=500cm3
d=1,1g/cm3
m=v*d
m=500*1,1
m=550g
mr=550g
Cp=8%
ms=Cp*mr/100%
ms=8*550/100
ms = 44g Na2S
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v=500cm3
d=1,1g/cm3
m=v*d
m=500*1,1
m=550g
mr=550g
Cp=8%
ms=Cp*mr/100%
ms=8*550/100
ms = 44g Na2S