Ile gramów KOH otrzymamy po odparowaniu do sucha 0,5dm3 roztworu 20% o gęstości 1,18 g/cm3
Bardzo prosze o pomoc
mr=0,5dm³*1,18g/cm³=500cm³*1,18g/cm³=590g
Cp=20%
ms=?
Cp=ms/mr * 100% /*mr
Cp*mr=ms*100% /:100%
ms=Cp*mr/100%
ms=20%*590g/100%
ms=118g
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mr=0,5dm³*1,18g/cm³=500cm³*1,18g/cm³=590g
Cp=20%
ms=?
Cp=ms/mr * 100% /*mr
Cp*mr=ms*100% /:100%
ms=Cp*mr/100%
ms=20%*590g/100%
ms=118g