oblicz steżenie procentowe roztworu amoniaku o stęzeniu 15,7 mol/dm3 i gęstości 0,89 g/cm3
M NH3=17g/mol
Cm=15,7mol/dm3
d=0,89g/cm3 = 890g/dm3
Cp=?
Cp = Cm*M*100%/d
Cp = 15,7*17*100/890
Cp = 30%
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M NH3=17g/mol
Cm=15,7mol/dm3
d=0,89g/cm3 = 890g/dm3
Cp=?
Cp = Cm*M*100%/d
Cp = 15,7*17*100/890
Cp = 30%