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V = m/d = 500/1,5 = 333,3 cm3 = 0,333 dm3
masa molowe:
M = 23 + 16 + 1 = 40 g
liczba moli:
n = ms/M = 90/40 = 2,25
stężenie molowe:
Cm = n/V = 2,25/0,333 = 6,76 mol/dm3
n=90 :40= 2,25
Mnaoh=40
d=mr:vr
vr=mr :d
vr=500:1,5=333,333
Cmol=n:Vr =2,25/0,333 = 6,76 mol/dm3
proszę:)
90g - 0,333 dm^3
x- 1dm^3
x=90gx1dm^3/0.333dm^3=270.27g
MNaOH=40g/mol
40g - 1 mol
270.27g- x
x=270.27gx1mol/40g=6.76mola
Cm=n/Vr=6.76mola/dm^3