ile g soli jest w 0,4l r-ru 6% o gęst. 1,2g/cm3. Wystarczy mi tylko wynik.
V = 0,4l = 0,4dm³ = 400cm³
d = 1,2g/cm³
m = dV
m = 1,2g/cm³ x 400cm³ = 480g
ms = mr x cp/100%
ms = 480g x 6%/100% = 28,8g
Pozdrawiam :)
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V = 0,4l = 0,4dm³ = 400cm³
d = 1,2g/cm³
m = dV
m = 1,2g/cm³ x 400cm³ = 480g
ms = mr x cp/100%
ms = 480g x 6%/100% = 28,8g
Pozdrawiam :)