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Obliczamy masę molową Na2CO3 * 10 H2O.
M = 2*23[g/mol] + 12[g/mol] + 3*16[g/mol] + 10* 18[g/mol] = 286[g /mol].
Układamy proporcję :
286[g ] Na2CO3 * 10H2O - zawiera 106[g] Na2CO3;
30 [g] Na2CO3*10H2O - x[g] Na2CO3.
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x = 3180 / 286 = 11,1 [g] Na2CO3.
ms = 11,1[g].
mw = 200[cm3] * 1[g /cm3] = 200[g].
mr = 30 [g] + 200 [g] = 230[g].
Cp = (ms*100[%] ) / mr.
Cp = (11,1* 100 ) / 230 = 4,83[ %] .
Odp. Cp = 4,83 [%].
Z poszanowaniem : zbigniew63.