Do 200cm3 dwudziesto procentowego (20%) roztworu NaCl o gęstości 1,2 g/cm3 dodano 50g wody. Oblicz stężenie procentowe otrzymanego roztworu.
Dam najjj
Dam najjj
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V=200cm3
d=1,2 g/cm3
Cp1=20%
Szukane:
mr1=?
ms=?
Cp2=?
mr2=?
mr1=d*V
ms=Cp*mr1/100%
Cp2=ms*100%/mr2
mr2=mr1+50g
Obliczenia:
mr1=1,2 g/cm3*200cm3
mr1=240g
ms=20%*240g/100%
ms=48g
mr2=240g+50g
mr2=290g
Cp2=48g*100%/290g
Cp2=16,55%