do 30 cm3 15% zasady sodowej d=1,2g/cm3 dodano 200cm3 wody oblicz stezenie molowe roztworu . M NaOH= 40g?mol
d=m/V
m= d*V
V= 30cm3
Cp= 15%
d= 1,2g/cm3
m= 1,2g/cm3 * 30cm3= 36g
200cm3H20= 200gH2O
ms= Cp * mr/100%
ms= 15% * 36g/100%
ms= 5,4g
Vr2= 200cm3 + 30cm3= 230cm3= 0,23dm3
ms=bez zmian
MNaOH= 40g/cmol
Cm= ms/M*V
Cm= 5,4g / 40g/mol * 0,23dm3Cm= 0,587dm3
Pozdrawiam, kate66 ;)
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d=m/V
m= d*V
V= 30cm3
Cp= 15%
d= 1,2g/cm3
m= 1,2g/cm3 * 30cm3= 36g
200cm3H20= 200gH2O
ms= Cp * mr/100%
ms= 15% * 36g/100%
ms= 5,4g
Vr2= 200cm3 + 30cm3= 230cm3= 0,23dm3
ms=bez zmian
MNaOH= 40g/cmol
Cm= ms/M*V
Cm= 5,4g / 40g/mol * 0,23dm3
Cm= 0,587dm3
Pozdrawiam, kate66 ;)