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Cm=15 mol/dm3
M H2SO4=2u+32u+64u=98g/mol
d=1,42g/cm3=1420 g/dm3
C%=Cm*M*100%/d=15*98*100%/1420=103,52% ?
dane do zadania mi się nie podobają...
2. Zmieszano 400g 25% roztworu chlorku magnezu ze 200g 10% tego roztworu. Oblicz stężenie procentowe otrzymanego roztworu.
mr1=400g
Cp1=25%
mr2=200g
Cp2=10%
mr3=?
ms3=?
Cp3=?
mr3=400g+200g=600g
ms1=Cp1*mr1/100%=25%*400g/100%=100g
ms2=Cp2*mr2/100%=10%*200g/100%=20g
ms3=100g+20g=120g
Cp3=ms*100%/mr=120*100%/600=20%