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2/
m=ro *V
zamianiam 3 dm^3 na cm wiec to bedzie bodaj 3000 cm szescienne
m= 7,2 * 3000 = 21,600 g
3. masa calego zwiazku = 56*2+48 = 160 g
% zelaza
112/160 * 100% = 70 %
% tlenu - 30 %
b) m calego 232 g
% Fe = 168/232 * 100 % = 72 %
% tlenu - 28 % w przyblizeniu