Naiknya air di dalam pipa kapiler yang diameternya 0,6 mm apabila tegangan permukaan air 72,8 dyne/cm adalah...
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d=0,6 mm
tegangan permukaan air =72,8 dyne
L=1 gr/cm3
Derajat=0°
G=9,8m/s=9.80cm/s2
Maka : H????
h=2.y.cos Ѳ/P f .g.r
=2(72,8 dyne/cm) : (1 gr/cm2)x
(980cm/s2)(0.03cm)
=145.6 dyne/cm : 29.4 gr/cm
=4.95 cm