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m=1kg
v=40m/s
s=5000m
wzór
f=a*m
v=s/t
a=v/t
rozwiązanie;
40m/s=5000m/t
t=125s
a=40m/s/125s
a=0,32m/s²
f=1kg=0,32m/s²=0,32N
odp; Srednia siła wynosi 0,32N;)