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Verified answer
Materi : Asam BasaSub materi : Larutan Penyangga
Kata kunci : penyangga, buffer
NaOH + CH3COOH ---> CH3COONa + H2O
Gunakan rumus lar. penyangga asam
pH = 5 ---> [H+] = 10^-5 M
10^-5 = 10^-5 × [Asam]/[Garam]
[Asam] = [Garam]
Pd sistem larutan penyangga terdiri dari SISA asam lemah (CH3COOH) dgn garamnya (CH3COONa).
CH3COOH: 100 × 0.1 = 10 mmol
Diketahui jumlah mmol asam = jumlah mmol garamnya sehingga
[CH3COOH] = [CH3COONa]
10 - x = x
x = 5 mmol
NaOH: 5 mmol dlm 100 mL larutan tsb.
Massa NaOH yg ditambahkan:
5/100 × 40 = 2 gram
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