Odpowiedź:
mZwiązku chemicznego = 23*2 + 32 + 16*4 = 142
mNa - 23u
mS - 32
mO - 16u
m%Na = 46/142*100% = 32,4%
m%S = 32/142*100% = 22,5%
m%O = 64/142*100% = 45,1%
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Odpowiedź:
mZwiązku chemicznego = 23*2 + 32 + 16*4 = 142
mNa - 23u
mS - 32
mO - 16u
m%Na = 46/142*100% = 32,4%
m%S = 32/142*100% = 22,5%
m%O = 64/142*100% = 45,1%