Odpowiedź:
a)
H H H
I I I
H-C≡C - C -H +H-Cl--> H-C =C- C -H
b)
/ \ / \_Br
I O I + Br2---FeBr3---> I O I + HBr↑
\ / \ /
benzen bromobenzen
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Odpowiedź:
a)
H H H
I I I
H-C≡C - C -H +H-Cl--> H-C =C- C -H
I I I
H H H
b)
/ \ / \_Br
I O I + Br2---FeBr3---> I O I + HBr↑
\ / \ /
benzen bromobenzen