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Lo= 50 cm
Δt= 110-10= 100°C
ΔL= 50,05-50= 0,05 cm
Dit:
α=..?
Penye:
α= ΔL/(Lo.Δt)
α= 0,05/(50×100)
α= 0,05/5000
α= 0,00001 /°C
Lo = 50 cm
ΔL = 50,05 - 50= 0,05 cm
Δt = 110-10= 100°C
Dit :
α ..?
Dij :
α = ΔL / ( Lo x Δt )
α = 0,05 / ( 50 × 100 )
α = 0,05 / 5000
α = 0,00001 /°C
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