Question

Cepet y ini buat besok

Answer 1

Penjelasan dengan langkah-langkah:

2

diketahui :

• jarak pada prta = 4 cm
• jarak yg sebenarnya = 120 km

skala = 4 banding 120

= 4 : 4 banding 120 : 4

= 1 banding 30

3

• 1m = 100cm
• 30.000cm = 300m
• 1km = 1000m

30.000 cm + 1km

= 300m + 1000m

= 1.300m

4

[tex] \frac{1}{2} + 1 \frac{1}{4} + \frac{1}{4} [/tex]

[tex] = \frac{1}{2} + \frac{5}{4} + \frac{1}{4} [/tex]

[tex] = \frac{7}{4} + \frac{1}{4} [/tex]

[tex] = \frac{8}{4} [/tex]

[tex] = 2[/tex]

5

[tex]1.2 \times 2 \times 0.5[/tex]

[tex] = 1.2 \times 1[/tex]

[tex] = 1.2[/tex]

6

• 5 menit = 300 detik
• debit = 3liter/20detik

volume air setelah 5 menit

= 300 : 20 x 3liter

= 15 x 3liter

= 45liter

7

[tex]kecepatan = \frac{jarak}{waktu} [/tex]

[tex] = \frac{400m}{2menit} [/tex]

[tex] = \frac{200m}{menit} [/tex]

[tex] = \frac{200m \times 6}{jam} [/tex]

[tex] = \frac{1.200m}{jam} [/tex]

[tex] = \frac{1.2km}{jam} [/tex]

8

• volume = 60liter
• debit = 20cm³/detik = 20liter/detik

[tex]waktu = volume \div debit[/tex]

[tex] = 60liter \div \frac{20liter}{detik} [/tex]

[tex] = 3detik[/tex]

9

[tex]debit = \frac{volume}{waktu} [/tex]

[tex] = \frac{240liter}{20menit} [/tex]

[tex] = \frac{12 liter}{menit} [/tex]

10

• jarak pada peta = 4cm
• jarak yg sebenarnya = 80km

skala

= jarak peta :jarak yg sebenarnya

= 4 : 80

= 1 : 20