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Pembahasan
Dik l1 = 1000 m
T1 = 20 C
T2 = 150 C
α = 1,9 × 10⁻⁵/°C
Dit L2 . . .?
jawab.
L2 = l1 + (l1. α .ΔT)
= 1000 + (1000 .1,9 × 10⁻⁵ . (150 - 20))
= 1000 + 2,47
= 1002,47 meter
Cara lain
L2 = l1 + Δx
= l1 +l1 (1 + α . ΔT)
= 1000 + 1000 (1 + (1,9 × 10⁻⁵ . (150 - 20))
= 1000 +1000 (1 + 247 x 10⁻⁵)
= 1002,47 m
panjang kuningan tersebut pada suhu 150°C yaitu 1002,47 meter
Semoga membantu :) D jadikan jwb terbaik ya