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= log(√9 x 15 ÷ √25)
= log(3x15÷5)
= log3²
= 2
jawaban : B
8) (²log9 + ²log24)/²log6
= ²log(9x24)/²log6
= ²log216/²log6
= 6log216
= 6log6³
= 3
jawaban : A
9) 2. ²log a = ²log(3a -4) + 1
²log a² = ²log(3a - 4) + ²log2
a² = 3a - 4 + 2
a² - 3a + 2 = 0
(a -2)(a-1) = 0
a = 1 atau a = 2